The minor radius of an ellipse is found by identifying the smaller value between 'a' and 'b' in its standard equation form: (x−h)²/a² + (y−k)²/b² = 1
.
An ellipse is a closed curve for which the sum of the distances from any point on the curve to two fixed points (called foci) is constant. It has two primary radii: the major radius and the minor radius. These define the ellipse's shape and dimensions.
Understanding the Ellipse's Standard Equation
To accurately find the minor radius, it's crucial to understand the standard form of an ellipse's equation. The general equation of an ellipse centered at (h, k)
is given by:
(x−h)²/a² + (y−k)²/b² = 1
Here's what each component represents:
- (h, k): The coordinates of the center of the ellipse.
- a: The distance from the center to the ellipse along the horizontal axis (if
a²
is under(x-h)²
) or half the length of the major or minor axis. - b: The distance from the center to the ellipse along the vertical axis (if
b²
is under(y-k)²
) or half the length of the major or minor axis.
Key Insight from Reference:
The provided reference explicitly states: "The equation of an ellipse written in the form (x−h)²/a² + (y−k)²/b² = 1
. The center is (h,k)
and the larger of a
and b
is the major radius and the smaller is the minor radius."
Identifying the Minor Radius
Based on the standard equation and the definition, the process for identifying the minor radius is straightforward:
- Locate
a²
andb²
: In the standard form(x−h)²/a² + (y−k)²/b² = 1
, identify the denominatorsa²
andb²
. - Calculate
a
andb
: Take the square root ofa²
to finda
and the square root ofb²
to findb
. - Compare
a
andb
: Determine which of these two values (a
orb
) is smaller. - The Smaller Value is the Minor Radius: The smaller of
a
andb
is, by definition, the minor radius of the ellipse.
Practical Example
Let's consider an example to illustrate:
Question: Find the minor radius of the ellipse given by the equation: (x-2)²/9 + (y+1)²/25 = 1
Solution:
-
Identify
a²
andb²
:- From
(x-2)²/9
, we havea² = 9
. - From
(y+1)²/25
, we haveb² = 25
.
- From
-
Calculate
a
andb
:a = √9 = 3
b = √25 = 5
-
Compare
a
andb
:a = 3
b = 5
- Comparing these values,
3
is smaller than5
.
-
Determine Minor Radius:
- Therefore, the minor radius of the ellipse is 3. In this case,
b=5
would be the major radius.
- Therefore, the minor radius of the ellipse is 3. In this case,
Here's a summary table for clarity:
Ellipse Equation Component | Value from Example | Description |
---|---|---|
a² |
9 |
Denominator under (x-h)² |
b² |
25 |
Denominator under (y-k)² |
a |
√9 = 3 |
Half-axis length (horizontal) |
b |
√25 = 5 |
Half-axis length (vertical) |
Minor Radius | 3 | The smaller value between a and b |
Major Radius | 5 |
The larger value between a and b |
Understanding how to find the minor radius is fundamental in various fields, from astronomy (describing planetary orbits) to engineering (designing elliptical gears or structures).