What is 1 2 4 8 16 up to 64 terms?

This sequence is a geometric sequence where each term is found by multiplying the previous term by a constant. In this case, the constant is 2.

To find the 64th term, we can use the formula:

• *a_n = a₁ r^(n-1)**

where:

• a_n is the nth term
• a₁ is the first term (which is 1)
• r is the common ratio (which is 2)
• n is the number of terms (which is 64)

Therefore, the 64th term is:

• *a₆₄ = 1 2^(64-1) = 2⁶³ = 9,223,372,036,854,775,808**