The standard form of a parabola, represented as y = ax² + bx + c
, can be directly derived from its vertex form, y = a(x-h)² + k
, by expanding and simplifying the expression.
Understanding Parabola Forms
Parabolas are fundamental shapes in mathematics, and their equations can be expressed in different forms, each highlighting specific characteristics.
Vertex Form of a Parabola
The vertex form of a parabola is given by:
y = a(x-h)² + k
In this form:
(h, k)
represents the coordinates of the parabola's vertex, which is the lowest or highest point on the parabola.a
determines the parabola's direction of opening and its vertical stretch or compression.- If
a > 0
, the parabola opens upwards. - If
a < 0
, the parabola opens downwards.
- If
This form is particularly useful for quickly identifying the vertex and the axis of symmetry (x = h
).
Standard Form of a Parabola
The standard form of a parabola is expressed as:
y = ax² + bx + c
In this form:
a
serves the same purpose as in the vertex form, indicating the direction and stretch.c
represents the y-intercept of the parabola (where the parabola crosses the y-axis, whenx=0
).b
influences the position of the vertex and the axis of symmetry.
The standard form is commonly used for solving quadratic equations (e.g., finding x-intercepts using the quadratic formula) and for graphing.
Feature | Vertex Form y = a(x-h)² + k |
Standard Form y = ax² + bx + c |
---|---|---|
Vertex | Immediately visible: (h, k) |
Calculated: x = -b/(2a) , then substitute x into equation for y |
Y-intercept | Set x=0 and solve for y |
Immediately visible: (0, c) |
Axis of Symmetry | x = h |
x = -b/(2a) |
Direction | a > 0 (up), a < 0 (down) |
a > 0 (up), a < 0 (down) |
Converting Vertex Form to Standard Form
To convert a parabola from its vertex form y = a(x-h)² + k
to its standard form y = ax² + bx + c
, you need to expand the squared term and simplify the expression.
Here are the step-by-step instructions:
-
Start with the vertex form:
y = a(x-h)² + k
-
Expand the squared binomial
(x-h)²
:
Recall that(A-B)² = A² - 2AB + B²
. So,(x-h)² = x² - 2xh + h²
.
Substitute this back into the equation:
y = a(x² - 2xh + h²) + k
-
Distribute
a
to each term inside the parentheses:
y = ax² - 2axh + ah² + k
-
Rearrange the terms to match the standard form
y = ax² + bx + c
:
Group thex
term and the constant terms:
y = ax² + (-2ah)x + (ah² + k)
By comparing this result to y = ax² + bx + c
, we can see the direct relationships:
- The
a
coefficient remains the same. - The
b
coefficient in standard form is-2ah
. - The
c
constant in standard form isah² + k
.
Example: Converting from Vertex Form to Standard Form
Let's convert the parabola given in vertex form y = 3(x-2)² + 5
to its standard form.
Here, a = 3
, h = 2
, and k = 5
.
-
Start with the vertex form:
y = 3(x-2)² + 5
-
Expand
(x-2)²
:
(x-2)² = x² - 2(x)(2) + 2² = x² - 4x + 4
Substitute this back:
y = 3(x² - 4x + 4) + 5
-
Distribute
a
(which is 3):
y = 3 * x² - 3 * 4x + 3 * 4 + 5
y = 3x² - 12x + 12 + 5
-
Combine constant terms:
y = 3x² - 12x + 17
Thus, the standard form of the parabola y = 3(x-2)² + 5
is y = 3x² - 12x + 17
.