The exact answer to the question "How many different numbers can be formed out of all the digits 111223?" is 60.
Understanding Permutations with Repetition
When forming numbers from a set of digits where some digits are repeated, the number of unique arrangements (permutations) is calculated using a specific formula. This is different from permutations where all items are distinct. The question implies forming six-digit numbers by using all the provided digits.
The formula for permutations with repetition is:
$$ \frac{n!}{n_1! n_2! \dots n_k!} $$
Where:
- $n$ is the total number of items (digits) available.
- $n_1, n_2, \dots, n_k$ are the counts of each distinct item that is repeated.
Applying the Formula to the Digits 111223
Let's break down the given digits:
- Total number of digits ($n$) = 6
- Digit '1' appears ($n_1$) = 3 times
- Digit '2' appears ($n_2$) = 2 times
- Digit '3' appears ($n_3$) = 1 time
Now, we can apply the formula:
-
Calculate the factorial of the total number of digits:
$6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720$ -
Calculate the factorial for each repeated digit's count:
- For '1' (3 times): $3! = 3 \times 2 \times 1 = 6$
- For '2' (2 times): $2! = 2 \times 1 = 2$
- For '3' (1 time): $1! = 1$ (This is included for completeness but doesn't change the product).
-
Divide the total factorial by the product of the factorials of the repeated counts:
Number of unique numbers = $ \frac{6!}{3! \times 2! \times 1!} = \frac{720}{6 \times 2 \times 1} = \frac{720}{12} = 60 $
Therefore, there are 60 unique six-digit integers that can be formed from the digits 111223.
Practical Insights
This method is crucial for problems involving arrangements of items with identical elements. For instance, it's used in:
- Calculating the number of unique words that can be formed from a set of letters (e.g., how many unique words can be formed from the letters of "MISSISSIPPI").
- Determining unique sequences in genetic codes or data strings where certain characters repeat.
Summary of Digits and Counts:
Digit | Count | Factorial of Count |
---|---|---|
1 | 3 | $3! = 6$ |
2 | 2 | $2! = 2$ |
3 | 1 | $1! = 1$ |
Total | 6 |
The calculation confirms that there are 60 different numbers that can be formed using all the digits 111223.