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How to find zeros of a polynomial?

Published in Polynomial Zeros 6 mins read

To find the zeros of a polynomial, you need to determine the values of the variable for which the polynomial expression equals zero. These values are also known as the roots of the polynomial. Graphically, the zeros correspond to the x-coordinates where the polynomial's graph intersects or touches the x-axis.

What Are Zeros of a Polynomial?

The zeros of a polynomial are the specific input values (often 'x') for which the polynomial's output (often 'P(x)') is equal to 0. Essentially, if you have a polynomial $P(x)$, its zeros are the solutions to the equation $P(x) = 0$.

Aspect Description
Definition Values of the variable (e.g., x) that make the polynomial equal to zero.
Graphical Link The x-coordinates of the points where the graph of the polynomial crosses or touches the x-axis. These are also known as the x-intercepts.
Significance They provide critical information about the polynomial's behavior, such as its intercepts and factors.
Number of Zeros A polynomial of degree 'n' will have exactly 'n' zeros in the complex number system, counting multiplicity (Fundamental Theorem of Algebra).

Methods for Finding Zeros

There are several methods to find the zeros of a polynomial, ranging from visual inspection to complex algebraic computations. The most suitable method depends on the degree of the polynomial and its specific form.

Graphical Method

The simplest way to conceptualize zeros is through their graphical representation.

  • Process: Plot the polynomial function on a coordinate plane. Observe where the graph line cuts or touches the x-axis. The x-coordinates of these intersection points are the zeros of the polynomial.
  • Insight: This method provides a visual approximation of the zeros and helps confirm algebraic results. It's especially useful for understanding the number and approximate location of real zeros.
  • Example: For a polynomial like $P(x) = x^2 - 4$, its graph is a parabola that crosses the x-axis at $x = -2$ and $x = 2$. Therefore, the zeros are -2 and 2.

Algebraic Methods

Algebraic methods provide exact solutions for the zeros.

1. Factoring Polynomials

Factoring is a powerful technique where you break down the polynomial into simpler expressions (factors). If a polynomial can be factored, its zeros can be found by setting each factor to zero.

Quadratic Polynomials ($ax^2 + bx + c = 0$)

For polynomials of degree 2, commonly known as quadratic equations, several factoring techniques apply:

  • Direct Factoring:

    • Process: Find two numbers that multiply to $ac$ and add to $b$. Use these numbers to rewrite the middle term ($bx$), then factor by grouping.
    • Example: Find the zeros of $P(x) = x^2 - 5x + 6$.
      1. Set $P(x) = 0$: $x^2 - 5x + 6 = 0$.
      2. Factor the quadratic: $(x - 2)(x - 3) = 0$.
      3. Set each factor to zero:
        • $x - 2 = 0 \Rightarrow x = 2$
        • $x - 3 = 0 \Rightarrow x = 3$
      • The zeros are 2 and 3.
  • Quadratic Formula:

    • Process: When factoring is difficult or impossible, the quadratic formula provides a direct solution for any quadratic equation $ax^2 + bx + c = 0$.
    • Formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
    • Example: Find the zeros of $P(x) = 2x^2 + x - 3$.
      1. Here, $a = 2$, $b = 1$, $c = -3$.
      2. Substitute into the formula:
        $x = \frac{-(1) \pm \sqrt{(1)^2 - 4(2)(-3)}}{2(2)}$
        $x = \frac{-1 \pm \sqrt{1 + 24}}{4}$
        $x = \frac{-1 \pm \sqrt{25}}{4}$
        $x = \frac{-1 \pm 5}{4}$
      3. Two possible solutions:
        • $x_1 = \frac{-1 + 5}{4} = \frac{4}{4} = 1$
        • $x_2 = \frac{-1 - 5}{4} = \frac{-6}{4} = -\frac{3}{2}$
      • The zeros are 1 and -3/2.
Higher-Degree Polynomials

For polynomials of degree 3 or higher, factoring can be more complex:

  • Factoring by Grouping:

    • Process: Applicable to polynomials with four terms. Group terms and factor out common monomials.
    • Example: Find the zeros of $P(x) = x^3 + 2x^2 - 9x - 18$.
      1. Set $P(x) = 0$: $x^3 + 2x^2 - 9x - 18 = 0$.
      2. Group terms: $(x^3 + 2x^2) - (9x + 18) = 0$.
      3. Factor common terms from each group: $x^2(x + 2) - 9(x + 2) = 0$.
      4. Factor out the common binomial: $(x + 2)(x^2 - 9) = 0$.
      5. Factor the difference of squares $(x^2 - 9)$: $(x + 2)(x - 3)(x + 3) = 0$.
      6. Set each factor to zero:
        • $x + 2 = 0 \Rightarrow x = -2$
        • $x - 3 = 0 \Rightarrow x = 3$
        • $x + 3 = 0 \Rightarrow x = -3$
      • The zeros are -2, 3, and -3.
  • Special Product Formulas: Recognize patterns like sum/difference of cubes ($a^3 \pm b^3$) or perfect cubes.

2. Rational Root Theorem and Synthetic Division

For higher-degree polynomials that don't easily factor by grouping, the Rational Root Theorem helps identify potential rational zeros.

  • Rational Root Theorem: This theorem states that if a polynomial $P(x) = a_nx^n + ... + a_0$ has integer coefficients, then any rational zero must be of the form $p/q$, where $p$ is a factor of the constant term ($a_0$) and $q$ is a factor of the leading coefficient ($a_n$).
  • Process:
    1. List all possible rational roots ($p/q$).
    2. Test these potential roots using synthetic division.
    3. If synthetic division yields a remainder of zero, the tested value is a zero, and the resulting quotient is a depressed polynomial (one degree lower).
    4. Repeat the process on the depressed polynomial until you reach a quadratic, which can then be solved using factoring or the quadratic formula.
  • Example: Find the zeros of $P(x) = x^3 - x^2 - 10x - 8$.
    1. Factors of the constant term ($p$): $\pm1, \pm2, \pm4, \pm8$.
    2. Factors of the leading coefficient ($q$): $\pm1$.
    3. Possible rational roots ($p/q$): $\pm1, \pm2, \pm4, \pm8$.
    4. Test $x = -1$ using synthetic division:
      -1 | 1  -1  -10  -8
         |    -1    2   8
         ----------------
           1  -2   -8   0

      Since the remainder is 0, $x = -1$ is a zero. The depressed polynomial is $x^2 - 2x - 8$.

    5. Solve the quadratic $x^2 - 2x - 8 = 0$:
      • Factor: $(x - 4)(x + 2) = 0$.
      • Set factors to zero: $x - 4 = 0 \Rightarrow x = 4$; $x + 2 = 0 \Rightarrow x = -2$.
    • The zeros are -1, 4, and -2.

3. Numerical Methods (Advanced)

For polynomials of degree 5 or higher, there is no general algebraic formula (like the quadratic formula) to find the zeros. In such cases, or when exact zeros are not integers or simple fractions, numerical methods are employed.

  • Process: Algorithms like Newton's Method or the Bisection Method iteratively approximate the zeros to a desired level of precision. These methods typically require a starting guess and are often implemented using software.
  • Insight: While not yielding exact analytical solutions, numerical methods are crucial in practical applications where approximations are sufficient.

Practical Tips

  • Always try to factor first, especially for quadratics and cubics that might be factorable by grouping.
  • Use the Rational Root Theorem for higher-degree polynomials to find initial rational roots, which can then simplify the polynomial for further analysis.
  • Verify your answers by plugging the found zeros back into the original polynomial to ensure the result is zero, or by checking against a graph.
  • Utilize online calculators or graphing tools (e.g., Desmos, Wolfram Alpha) for complex polynomials or to visually confirm results.

Understanding and applying these methods allows you to systematically find the zeros of various types of polynomials, a fundamental skill in algebra and higher mathematics.