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What is the formula for Taylor's theorem with Lagrange's form of remainder?

Published in Taylor Series Remainder 5 mins read

The formula for Taylor's Theorem with Lagrange's form of remainder provides a precise way to approximate a function with a polynomial and quantify the error in that approximation.

Understanding Taylor's Theorem

Taylor's Theorem is a powerful tool in calculus used to approximate a function $f(x)$ around a specific point $a$ using a polynomial. This polynomial, known as the Taylor polynomial, is constructed from the function's derivatives evaluated at that central point $a$. The theorem also provides a remainder term that specifies the exact error of this polynomial approximation.

The Role of the Remainder Term

When we approximate a function using a finite number of terms in a Taylor polynomial, there's always a difference between the actual function value and the value provided by the polynomial. This difference is known as the remainder or error term. Lagrange's form of the remainder gives an explicit expression for this error, making it possible to bound or estimate the accuracy of the approximation.

The Formula for Taylor's Theorem with Lagrange's Remainder

For a function $f(x)$ that is $(n+1)$ times differentiable on an interval containing both $a$ and $x$, Taylor's Theorem states:

$f(x) = P_n(x) + R_n(x)$

Where $P_n(x)$ is the $n$-th degree Taylor polynomial given by:

$P_n(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f'''(a)}{3!}(x-a)^3 + \dots + \frac{f^{(n)}(a)}{n!}(x-a)^n$

This can be more compactly expressed using summation notation:

$Pn(x) = \sum{k=0}^{n} \frac{f^{(k)}(a)}{k!}(x-a)^k$

And $R_n(x)$ is the Lagrange form of the remainder, which quantifies the error:

$R_n(x) = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

In this remainder term, $c$ is some unknown number that lies strictly between $a$ and $x$. The existence of such a $c$ is guaranteed by the Mean Value Theorem.

Key Components of the Formula

Let's break down the individual parts of this important formula:

  • $f(x)$: The original function being approximated.
  • $a$: The center or expansion point of the Taylor series. This is the specific point where the function and its derivatives are evaluated to construct the polynomial.
  • $n$: The degree of the Taylor polynomial. This indicates the highest order derivative included in the polynomial approximation.
  • $f^{(k)}(a)$: Represents the $k$-th derivative of the function $f$ evaluated at the point $a$. For $k=0$, it refers to the function itself, $f(a)$.
  • $k!$: The factorial of $k$, which is the product of all positive integers up to $k$.
  • $(x-a)^k$: A term representing the distance from the expansion point $a$ to the point $x$ at which the function is being approximated, raised to the power of $k$.
  • $P_n(x)$: The $n$-th degree Taylor polynomial, which is the sum of the first $(n+1)$ terms (from $k=0$ to $k=n$). This is the polynomial approximation itself.
  • $R_n(x)$: The Lagrange remainder term. This term captures the exact difference between the actual function value $f(x)$ and its polynomial approximation $P_n(x)$.
  • $f^{(n+1)}(c)$: The $(n+1)$-th derivative of the function $f$ evaluated at an unknown point $c$. This point $c$ is guaranteed to be between $a$ and $x$.

Table of Notations

Notation Description
$f(x)$ The function being approximated
$a$ The point around which the Taylor series is expanded (center)
$n$ The highest degree of the polynomial approximation
$f^{(k)}(a)$ The $k$-th derivative of $f$ evaluated at $a$
$k!$ The factorial of $k$
$P_n(x)$ The $n$-th degree Taylor polynomial
$R_n(x)$ The Lagrange form of the remainder term (the error)
$c$ A specific value existing strictly between $a$ and $x$
$(x-a)^k$ The distance from $a$ to $x$, raised to the $k$-th power

Practical Insights and Applications

Taylor's Theorem with Lagrange's remainder is not just a theoretical concept; it has significant practical implications:

  • Error Bounding: One of its primary uses is to estimate the maximum possible error when approximating a function with a Taylor polynomial. By finding the maximum value of $|f^{(n+1)}(c)|$ over the interval between $a$ and $x$, one can establish an upper bound for the approximation error.
  • Convergence Analysis: It serves as a fundamental tool for proving the convergence of Taylor series. If the remainder term $R_n(x)$ approaches zero as $n$ approaches infinity for a given $x$, then the infinite Taylor series converges to the actual function $f(x)$.
  • Basis for Numerical Methods: Many algorithms in numerical analysis, such as methods for solving differential equations or approximating definite integrals, are built upon the principles of Taylor's Theorem, leveraging the remainder term to control precision and assess accuracy.

Example Insight:

Consider approximating the sine function, $\sin(x)$, around $a=0$ (this is known as a Maclaurin series). If we use a 3rd degree Taylor polynomial ($n=3$), the formula would be:

$\sin(x) = \sin(0) + \sin'(0)(x-0) + \frac{\sin''(0)}{2!}(x-0)^2 + \frac{\sin'''(0)}{3!}(x-0)^3 + R_3(x)$
$\sin(x) = 0 + 1(x) + \frac{0}{2}x^2 + \frac{-1}{6}x^3 + R_3(x)$
$\sin(x) = x - \frac{x^3}{6} + R_3(x)$

Here, the remainder term $R_3(x)$ would be $\frac{f^{(4)}(c)}{4!}(x-0)^4 = \frac{\sin^{(4)}(c)}{24}x^4 = \frac{\sin(c)}{24}x^4$ for some $c$ between $0$ and $x$. This remainder term tells us the exact error of using $x - \frac{x^3}{6}$ to approximate $\sin(x)$. For small $x$, $x^4$ is very small, and $|\sin(c)| \le 1$, so the error is typically small.